Two point charges q 1 = 2.00 n C and q 2 = -6.10 n C are 0.100 m apart. Point A
ID: 2135662 • Letter: T
Question
Two point charges q1 = 2.00nC and q2 = -6.10nC are 0.100 mapart. Point A is midway between them; point B is 0.080 mfrom q1 and 0.060 m from q2 (the figure (Figure 1) ). Take the electric potential to be zero at infinity.
A.Find the potential at point A.
B. Find the potential at point B
C.
Find the work done by the electric field on a charge of 2.60nC that travels from point B to point A.
A A
Two point charges q1 = 2.00nC and q2 = -6.10nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from q1 and 0.060 m from q2 (the figure (Figure 1) ). Take the electric potential to be zero at infinity. Find the potential at point A. Find the potential at point B Find the work done by the electric field on a charge of 2.60nC that travels from point B to pointExplanation / Answer
Va = k*q1/0.05 - k*q2/0.05 = -738 v
Vb = k*q1/0.08 - k*q2/0.06= -690volts
W = (Vb-Va)*Q = 125*10^-9 Joules
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