Detail as below: Consider two cars, one a compact model (m = 768 kg) and the oth

Question

Detail as below:

Consider two cars, one a compact model (m = 768 kg) and the other an SUV (m = 2457 kg). The SUV is traveling at 16 m/s, while the compact car is traveling at an unknown speed v. If the two cars have the same momentum, what is v? m/s Two particles of mass mi = 1.8 kg and /t?2 = 2.3 kg are traveling with velocities = 4.7 m/s, and v2 = 2.5 m/s as shown in the figure below. What is the total momentum of this system? Be sure to give the magnitude and direction of the momentum, magnitude kg middot m/s direction degree above the x-axis

Explanation / Answer

3)

momentum=mass*velocity

since the momentums of the cars are equal

m1v1=m2v2

2457*16=768*v2

v2=51.1875m/s

velocity of the compact car=51.1875

4)

let i ,j represents unit vectors along positive x,y axis respectively

momentum of m1=m1v1 i

=1.8*4.7 i

=8.46 i

momentum of m2=m2v2 j

=2.3*2.5 j

=5.75 j

total momentum of the system=8.46i +5.75j

madnitude of the total momentum of system=(8.46^2+5.75^2)^0.5

=10.229kgm/s

direction of total momentum=tan^-1(5.75/8.46)

=38.003 degrees with positive x axis

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