A concave mirror has a radius of curvature equal to 24 cm. Use ray diagrams to l

Question

A concave mirror has a radius of curvature equal to 24 cm. Use ray diagrams to locate the image, if it exists, for an object near the axis at the distances labeled below. For each of the following cases, state whether the image is real or virtual, upright or inverted, and enlarged, reduced, or the same size as the object. (Do this on paper as well. Your instructor may ask you to turn in these diagrams.)

Explanation / Answer

a) Apply 1/f = 1/p + 1/q

the focal length is half the radius of curvature [f= 24/2 = 12]

1/12 = 1/55 + 1/q

q = 15.3 cm

The image is real (since q is positive). The image is inverted (since p and q are both positive). The image is reduced (since the q is smaller than p)

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b)

1/12 = 1/24 + 1/q

q = 24 cm

The image is real (since q is positive). The image is inverted (since p and q are both positive). The image is the same size as the object (since the q is the same as p)

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c)

1/12 = 1/12 + 1/q

q = 0

There is no image, the object is placed on the focal point.

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Part D)

1/12 = 1/8 + 1/q

q = -24 cm

The image is virtual (since q is negative). The image is upright (since p is positive and q is negative). The image is enlarged (since the magnitude of q is larger than p)

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