An electron with a kinetic energy of 2.00 keV (1 eV = 1.602 An electron with a k

Question

An electron with a kinetic energy of 2.00 keV (1 eV = 1.602

An electron with a kinetic energy of 2.00 keV (1 eV = 1.602 times 10-19 J) (See the figure attached.) is fired horizontally across a horizontally oriented nonconducting charged plate with a surface charge density of ? = +4.00 times 10-6 C/m2. Compute the initial velocity of the electron at x = 0. What is the electric field the electron experiences, if the horizontal plate is big enough to be considered as an infinite sheet? Calculate the acceleration of the electron. Estimate the time for the electron to take to travel a horizontal distance of 4.00 cm? What is the vertical deflection of the electron from the initial height, after it has traveled a horizontal distance of 4.00 cm?

Explanation / Answer

Initial velocity calculation is wrong. v^2=7.032 * 10^14 therefore v=2.652*10^7.

This changes the time = 1.508*10^-9

Vertical deflection = 45.5cm

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