A skier is gliding along at 4.3 m / s on horizontal, frictionless snow. He sudde

Question

A skier is gliding along at 4.3m/s on horizontal, frictionless snow. He suddenly starts down a 10? incline. His speed at the bottom is 10m/s What is the length of the incline?How long does it take him to reach the bottom? A skier is gliding along at 4.3m/s on horizontal, frictionless snow. He suddenly starts down a 10? incline. His speed at the bottom is 10m/s What is the length of the incline?How long does it take him to reach the bottom? A skier is gliding along at 4.3m/s on horizontal, frictionless snow. He suddenly starts down a 10? incline. His speed at the bottom is 10m/s What is the length of the incline?How long does it take him to reach the bottom? A skier is gliding along at 4.3m/s on horizontal, frictionless snow. He suddenly starts down a 10? incline. His speed at the bottom is 10m/s What is the length of the incline?How long does it take him to reach the bottom?

Explanation / Answer

For the length, apply PE + KE = KE

mgh .5mv^2 = .5mv^2 (mass cancels)

(9.8)(h) .5)(4.3)^2 = (.5)(10^2)

h = 4.16 m

Then the length = 4.16/sin(10)

Length = 23.9 m

For the time apply

d = (.5)(vf + vo)t

23.9 = (.5)(4.3 + 10)(t)

t = 3.34 sec

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