A 0.500-kg block, attached to a spring with length 0.60 m and force constant 40.

Question

A 0.500-kg block, attached to a spring with length 0.60 m and force constant 40.0 N/m , is at rest with the back of the block at point A A on a frictionless, horizontal air table (the figure (Figure 1) ). The mass of the spring is negligible. You move the block to the right along the surface by pulling with a constant 20.0-N horizontal force. What is the block's speed when the back of the block reaches point B , which is 0.25 m to the right of point A A? When the back of the block reaches point B , you let go of the block. In the subsequent motion, how close does the block get to the wall where the left end of the spring is attached?

Explanation / Answer

A) By the work-energy theorem ..
WD = (F x d) = KE gain (

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