A 1.95kg ball is connected by means of two massless strings to a vertical, rotat

Question

A 1.95kg ball is connected by means of two massless strings to a vertical, rotating rod. The strings are tied to the rod and form two sides of an equilateral triangle. The tension in the upper string is 49.2N.

If the length of each string is 1.60m, what is the tension in the lower string?

What is the speed of the ball?

A 1.95kg ball is connected by means of two massless strings to a vertical, rotating rod. The strings are tied to the rod and form two sides of an equilateral triangle. The tension in the upper string is 49.2N. If the length of each string is 1.60m, what is the tension in the lower string? What is the speed of the ball?

Explanation / Answer

forces on the block

upper sting vertical component of tension - weight = lower string vetical tension component

therefore tension in lower string = (Tsin 30 -Mg)/sin 30 =10.98 N

horizontal componenet of both the strings = mass x centripetal acceleration

V^2 = (T1cos 30 +T2 cos 30) l sin 60/m

v= 6.08 m/sec

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