The 10.00- V battery in the figure ( Figure 1 ) is removed from the circuit and

Question

The 10.00-V battery in the figure (Figure 1) is removed from the circuit and reinserted with the opposite polarity, so that its positive terminal is now next to point a. The rest of the circuit is as shown in the figure.

A Find the current through 3.00-? resistor.

B Find the current through 4.00-? resistor.

C Find the current through 10.00-? resistor.

D Find the potential difference Vab of point a relative to point b.

The 10.00-V battery in the figure (Figure 1) is removed from the circuit and reinserted with the opposite polarity, so that its positive terminal is now next to point a. The rest of the circuit is as shown in the figure. Find the current through 3.00-? resistor. Find the current through 4.00-? resistor. Find the current through 10.00-? resistor. Find the potential difference Vab of point a relative to point b.

Explanation / Answer

There is 10V / 5 ohms = 2 amps out of the 10V battery, with 2 amps thru the 3 ohm resistor.

There is 5V / 5 ohm = 1 amps out of the 5V battery, with 1 amp thru the 4 ohm resistor.

There is 2A + 1A = 3A thru the 10 ohm resistor.

The potential difference is (2A * 3 ohm) - (1A * 4 ohm) = 6V - 4V = 2 Volts.

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