a clear explanation of how to get them mass for my skier 65.0 kg In the figure,

Question

a clear explanation of how to get them

mass for my skier 65.0 kg

In the figure, a T-bar ski tow pulls a skier up a hill inclined at 10.0 degree above horizontal. The skier starts from rest and is pulled by a cable that exerts a tension T at an angle of 30.0 degree above the surface of the hill. The coefficient of kinetic friction between the skis and the snow is 0.100. What is the maximum tension in the cable if the starting acceleration is not to exceed 3.92 m/s2? Draw a free-body diagram (FBD) for the skier. Choose a coordinate system and draw a set of coordinate axes on your FBD for A. Determine the angle that each force makes with the positive x-axis. Make an x-y table with components of each force (consistent with your FBD) listed in the appropriate place. If there are any forces for which you cannot immediately calculate a numerical value, write it in symbolic form. Using your x-y force chart, apply Newton's Second Law to each direction to arrive at two separate equations. Fill in all known numerical values. Solve the equations for the unknown tension force. Express the tension force to the correct number of significant figures.

Explanation / Answer

perpendicular to the incline

T*sin30 + N = mg*cos10

N = mg*cos10 - Tsin30


along the incline



T*cos30 - mgsin10 - mue*N = ma

T*cos30 - mgsin10 - mue*(mg*cos10 - Tsin30) = ma


T = (ma + mgsin10+mue*mgcos10) / (cos30+mue*sin30)

T = (65*3.92 + 65*9.8*sin10+ 0.1*65*9.8*cos10) /(cos30+0.1*sin30)
T = 467.40 N

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