Tarzan, who weighs 618 N , swings from a cliff at the end of a convenient vine t

Question

Tarzan, who weighs 618 N, swings from a cliff at the end of a convenient vine that is 20.0 m long (see the figure). From the top of the cliff to the bottom of the swing, he descends by 3.2 m. If the vine doesn't break, what is the maximum of the tension in the vine?
8.16

Tarzan, who weighs 618 N, swings from a cliff at the end of a convenient vine that is 20.0 m long (see the figure). From the top of the cliff to the bottom of the swing, he descends by 3.2 m. If the vine doesn't break, what is the maximum of the tension in the vine? 8.16 times 102 N The vine will break if the force on it exceeds 803.7 N. Does the vine break? If yes, at what angle does it break (if no enter 180. deg)?

Explanation / Answer

w = 618 N, L = 20.0 m, h = 3.2 m, find the tension T

mgh = mv2/2

at the lowest point:

T - mg = mv2/L = 2mgh/L

?T = mg(1 + 2h/L) = w(1 + 2h/L) =815.76= 8.16*10^2

so the vine will break. since 816 > 803.7

---> the total tension in the vine is

T = Fc + Fgr

T = mg(cos(a) + (6.4 - 40(1 - cos(a))/20)

803.7 = 618(cos(a) + (6.4 - 40(1 - cos(a))/20)

solve for a and u will get the answer

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.