Consider a block attached to a spring. The block is stretched a distance x and r

Question

Consider a block attached to a spring.  The block is stretched a distance x and released.  

What is the block's position when its power is at a maximum?

I know that P = F v and I should differentiate and set dP/dt = 0.  But then how to solve for block's position?

Consider a block attached to a spring. The block is stretched a distance x and released. Consider a block attached to a spring. The block is stretched a distance x and released. I know that P = F v and I should differentiate and set dP/dt = 0. But then how to solve for block's position?

Explanation / Answer

conservation of energy principle

.5kx^2=.5mv^2

x=square root of(m/k)v

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