Consider a beam of electrons in a vacuum, passing through a very narrow slit of

Question

Consider a beam of electrons in a vacuum, passing through a very narrow slit of width 2.00um . The electrons then head toward an array of detectors a distance 0.9450 away. These detectors indicate a diffraction pattern, with a broad maximum of electron intensity (i.e., the number of electrons received in a certain area over a certain period of time) with minima of electron intensity on either side, spaced 0.512 from the center of the pattern. What is the wavelength of one of the electrons in this beam? Recall that the location of the first intensity minima in a single slit diffraction pattern for light is , where is the distance to the screen (detector) and is the width of the slit. The derivation of this formula was based entirely upon the wave nature of light, so by de Broglie's hypothesis it will also apply to the case of electron waves.

Explanation / Answer

Please follow the link below to see the solution of this problem.Only difference in the numerical values,but the concept is same.Please give me a good rating as i found this link after hard work. http://www.cramster.com/answers-apr-11/physics/177-de-broglie-relation-beam-electrons-vacuum-passing_1264997.aspx?rec=0

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