(A) A battery of ? = 2.10 V and internal resistance R = 0.450 ? is driving a mot

Question

(A) A battery of ? = 2.10 V and internal resistance R = 0.450 ? is driving a motor.  The motor is lifting a 2.0 N mass at constant speed v = 0.50 m/s.  Assuming no energy losses, find the current i in the circuit. Enter the lower current.

(B) Enter the higher current.

(C) Find the potential difference V across the terminals of the motor for the lower current.

(D) Find the potential difference V across the terminals of the motor for the higher current.

Discuss the fact that there are two solutions to this problem.

Explanation / Answer

if let V be the induced emf in motor and I be the currentthen I = [E - V]/R---------------------(1) as output power of motor is P=VI which is used to lift thatweight as power P=Fv here v is velocity of mass so VI=Fv ----------------(2) putting values of F and v as 2.0N and 0.50 m/s VI=1 V=1/I-----------------(3) from equation (3 ) in (1) we get I = [E - 1/I]/R
putting values we get quad equation in I I = [2.10 - 1/I]/0.450 we get I^2

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