Two objects (m1 = 4.95 kg and m2 = 2.60 kg) are connected by a light string pass

Question

Two objects (m1 = 4.95 kg and m2 = 2.60 kg) are connected by a light string passing over a light, frictionless pulley suspended over a table. The 4.95-kg object is released from rest at a point h = 4.00 m above the table, while the 2.60-kg object is resting on the table.

(a) Determine the speed of each object when the two pass each other.

(b) Determine the speed of each object at the moment the 4.95-kg object hits the table.

(c) How much higher does the 2.60-kg object travel after the 4.95-kg object hits the table?

Explanation / Answer

a) accelaration a = (m2-m1)*g/(m1+m2) = (4.95-2.6)*9.8 / (4.95+2.6) = 3.05 m/s^2

v^2-u^2 = 2*a*(h/2)

v = sqrt(2*3.05*2) = 3.492 m/s


b) v1 = sqrt(2*a*h = 4.939 m/s


c) y = v1^2/2g = 1.245m

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