A 57 - k g trampoline artist jumps upward from the top of a platform with a vert

Question

A 57-kg trampoline artist jumps upward from the top of a platform with a vertical speed of 5.6m/s .

If the trampoline behaves like a spring of spring constant 5.3

A 57-kg trampoline artist jumps upward from the top of a platform with a vertical speed of 5.6m/s . If the trampoline behaves like a spring of spring constant 5.3 times 104N/m , how far does he depress it? Express your answer to two significant figures and include the appropriate units. The Velocity as he lands on the trampoline is 8.4 m/s

Explanation / Answer

by using coservation of energy

1/2mv^2=1/2 k x^2+mgh

x= sqrt((m/k)*(v^2-2gh))

x=sqrt((57/5.3*10^4(8.4^2-2*9.8*2)

=0.1836 m

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