In the instant of the figure, two particles move in an xy plane. Particle P 1 ha

Question

In the instant of the figure, two particles move in an xy plane. Particle P1 has mass 6.83 kg and speed v1 = 6.88 m/s, and it is at distance d1 = 4.86 m from point O. Particle P2 has mass 9.75 kg and speed v2 = 3.08 m/s, and it is at distance d2 = 3.04 m from point O. What is the magnitude of the net angular momentum of the two particles about O?

In the instant of the figure, two particles move in an xy plane. Particle p1 has mass 6.83 kg and speed v1 = 6.88 m/s, and it is at distance d1 = 4.86 m from point O. Particle P2 has mass 9.75 kg and speed v2 = 3.08 m/s, and it is at distance d2=3.04 m from point O. What is the magnitude of the net angular momentum of the two particles about o? the tolerance is +/-2Percentage

Explanation / Answer

the magnitude of angular momentum = summation of mvr

= the resultant angular momentum = 6.83*6.88*4.86 + 9.75*3.08*3.04 =319.66

if the rotation of both are in same sense the angular momentum adds up and if they are in opposite sense then they subtract each other

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