need help please with these two questions. please show your work. so i can know
ID: 2144489 • Letter: N
Question
need help please with these two questions.
please show your work. so i can know w
hat you doing.
A wire of 58.0-cm length and 14.0-g mass crosses a uniform magnetic field of 435 mT. Both the wire and the magnetic field lie in a horizontal plane, making an angle of 60.0 degree with respect to each other, as depicted in the figure on page 1 of this handout. What is the minimum current (in mA) in the wire required to magnetically levitate the wire, i.e., so that the magnetic force on the wire exactly balances its weight? A metal wire of mass m slides frictionlessly on two horizontal rails spaced a distance d apart, as shown in the following figure. A uniform, vertical magnetic field B points out of the page. A constant current I flows from the battery along the bottom rail, across the slide wire, and back to the battery along the top rail. Find the speed and direction of motion of the wire after a time t, assuming it starts from rest at t = 0. (Hint: Show that the acceleration of the wire is constant, and then use the appropriate equation of 1D kinematics.)Explanation / Answer
1) I L B sin theta = mg
I = mg/( B L sin theta) = 14.0E-3*9.81/(.435*.58*sin(60 degrees))=0.629 A
2)
F = I d B = m a
a = I d B/m so constant acceleration
v = a t = I d Bt/m to the right
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