pleaase show your work correctly. the diagram is on the other question i posted

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pleaase show your work correctly.

the diagram is on the other question i posted please refer to it to answer number 7.

pleaase show your work correctly. the diagram is on the other question i posted please refer to it to answer number 7. Calculate the magnitude of the vertical component of the force that the wall exerts on the left end of the beam. A woman who weighs 487 N is leaning against a smooth vertical wall, as the drawing shows, (a) Find the force Fjsj (directed perpendicular to the wall) exerted on her shoulder by the wall. Find the vertical component of the force exerted on her shoes by the ground. By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows, with W| = 11.8 kg and m2 = 43.7 kg. The pulley can be treated as a uniform, solid, cylindrical disk. The downward acceleration of the 43.7 kg block is obser'ed to be exactly one-half the acceleration due to gravity. Noting that the tension in the rope is not the same on each side of the pulley, fmd the mass of the pulley. II kg

Explanation / Answer

7)

a) sum torque about bottom


-1310*L/2*cos(30) - 1800*L*cos(30) + T*L*sin(80) = 0

T=2158.9 N

sum forces in the x

N - 2158.9*cos(50) = 0
N = 1387.8 N

b) sum in the y

y - 1310 - 1800 + 2158.7*sin(50) = 0

y=1456.3 N

8)

a) sum torque about bottom
- 487*1.1*cos(60) + F*1.5*sin(60) = 0

F=206.2 N

9)

sum forces in the y

N - mg = 0
N = 487 N

10)

for block 2
m2 g - T2 = m2 a

for block 1

T1 - m1g = m1a

for pulley
r T2 - rT1 = 1/2 mr^2 alpha
T2 - T1 = 1/2 m a

sum equations

m2g - m1g = (m1 + m2 + 0.5*m) a

(43.7-11.8)*9.81 = (43.7+11.8+0.5*m)*9.81/2
m=16.6 kg

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