Help with part A and D Figure 2 - Using a potentiometer to measure the resistanc

Question

Help with part A and D

Figure 2 - Using a potentiometer to measure the resistance.

When the Wheatstone bridge is balanced, there is not current flow through the micrometer. This implies that the potential difference between AB is zero. This also means that VMA= VMBand VAN= VBN. If the amount of current flowing through R1is I1, this is also the amount flowing through R4. Similarly, if the amount of current flowing through R2is I2, this is also the amount flowing through R3. Using Ohm's law, we can write

Explanation / Answer

A)

Given that :

R4=(R3*R1)/R2

R2=ar

R3=(L-a)r , then R4=((L-a)*R1)/a

D) using solution from part A, R4=((1m - 0.487m)*287ohm)/0.487m

R4= 302.32 ohm

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