A small block of mass 65 g is released from rest at the top of a curved friction

Question

A small block of mass 65 g is released from rest at the top of a curved frictionless wedge of mass 233 g which sits on a frictionless horizontal surface as shown. The acceleration due togravity is 9.81 m/s2. Right is the positive direction.

When the block leaves the wedge, its velocity is 2.85 m/s to the right.

a) What is the velocity vb of the wedge after the block reaches the horizontal surface?
Answer in units of m/s

b) What is the height h of the wedge?

Answer in units of m

Explanation / Answer

a) M1 * V1 = M2 * V2 => 233 * Vb = 65 * 2.85 ==> Vb = .795 m/s b) Mgh = 1/2 (M1 * V1^2 ) + 1/2 (M2 * V2^2) ==> h = .41399 m

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