Four small aluminum spheres form the corners of a square whose side is 2.2 cm lo

Question

Four small aluminum spheres form the corners of a square whose side is 2.2 cm long. A fifth iron sphere is in the center of the square. m1 = 550 g m2 = 120 g m3 = 250 g m4 = 550 g m5 = 510 g

a) What is total gravitational force on the fifth sphere in thex-direction?

b) What is total gravitational force on the fifth sphere in they-direction?

c) What is magnitude of the total gravitational force on the fifth sphere?

Four small aluminum spheres form the corners of a square whose side is 2.2 cm long. A fifth iron sphere is in the center of the square. m1 = 550 g m2 = 120 g m3 = 250 g m4 = 550 g m5 = 510 g a) What is total gravitational force on the fifth sphere in thex-direction? b) What is total gravitational force on the fifth sphere in they-direction? c) What is magnitude of the total gravitational force on the fifth sphere?

Explanation / Answer

a.1.292*10^(-8) N b.-1.292*10^(-8) N c..1.8273*10^(-8) N

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