A rectangular circuit is moved at a constant velocity of v= 3.20m/s into, throug

Question

A rectangular circuit is moved at a constant velocity of v= 3.20m/s into, through, and then out of a uniform 1.50T magnetic field, as shown in the figure . The magnetic field region is considerably wider than 50.0cm . Assume that = 15.0ohms .

a)Find the magnitude of the current induced in the circuit as it is going into the magnetic field .

b)Find the magnitude of the current induced in the circuit as it is totally within the magnetic field but still moving .

c)Find the magnitude of the current induced in the circuit as it is moving out of the field .

Explanation / Answer

We know magnitude wise

E = d/dt

a) Let at time t its entered x distance

So

A = 0.75*x

= BA = 1.50*0.75*x

=> E = d/dt = 1.50*0.75*dx/dt = 1.50*0.75*v

= 3.6 V

=> I = E/R = 3.6/15 = 0.24 A

b) When fully immersed in the magnetic field area becomes constant

So E = d/dt = 0

=> I = E/R = 0

c) Again when its x out

Then areas under magnetic field

=> A = 0.75*(0.50-x)

   =  1.50*0.75*(0.50-x)

E = d/dt = -3.6 V

|I| = 3.6/15 = 0.24 A

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