A point charge q = +36.0 C moves from A to B separated by a distance magnitude 9

Question

A point charge q = +36.0 C moves from A to B separated by a distance

magnitude 9.1e-3 N direction TO THE RIGHT
A point charge q = +36.0 ½C moves from A to B separated by a distance d = 0.193 m in the presence of an external electric field of magnitude 253 N/C directed toward the right as in the following figure. (a) Find the electric force exerted on the charge.(I HAVE THIS ALREADY) magnitude 9.1e-3 N direction TO THE RIGHT (b) Find the work done by the electric force.(I HAVE THIS ALREADY) W = 1.75e-3 J (c) Find the change in the electric potential energy of the charge.(I HAVE THIS ALREADY) CHANGE IN PE = -1.75e-3 J (d) Find the potential difference between A and B. (HELP ME FIND THE VOLTAGES) VB - VA =? V

Explanation / Answer

Since it is in the uniform electric field we have E = dV/dx = > v = Edx ==> 253 * 0.193 =48.829

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