Can anyone help me with this question about currents? I\'ve posted on Chegg and

Question

Can anyone help me with this question about currents? I've posted on Chegg and not gotten a correct response so far!

Two very long straight conducting wires are perpendicular to the x-y plane. At point 'p', the magnetic field, shown in the figure below, is due to the currents in wires '1' and '2', with B=2.661e-4 T. Its components Bx=2.433e4 T and By=1.078e-4 T.

Calculate the magnitude of the current in wire 2 and in wire 1.

Please help if you can! I'm absolutely stumped, and need some step-by-step guidance.

Explanation / Answer

From right hand grip rule we get the direction of induced magnetic field by the current carrying wires.

Wire 1: B1 = - i1*0 x (x denotes the x-axis)

Wire 2: B2 = i2*0

the direction is (-3 x -2y)/13

Bx = - i1*0 - (i2*0) * 3/13 = 2.433 * 10-4

By = -(i2*0)* 2/13 = 1.078 * 10-4

Solving the equations, we get

i2 = - 154.65 A/m

i1 = -64.9 A/m

Note: 1> The negative directions show that the current is into the page contrary to our assumption that it is out of the page.

2> Since the wires are long, we can only calculate the current per unit length of the wire.

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