A 310 turn solenoid with a length of 22.0 cm and a radius of 1.40 cm carries a c

Question

A 310 turn solenoid with a length of 22.0 cm and a radius of 1.40 cm carries a current of 2.30 A. A second coil of four turns is wrapped tightly around this solenoid, so it can be considered to have the same radius as the solenoid. The current in the 310 turn solenoid increases steadily to 5.00 A in 0.900 s. I only need help with e. Please give me the most precise number possible.

(a) Use Ampere's law to calculate the initial magnetic field in the middle of the 310 turn solenoid.
Correct: Your answer is correct. T 4.1e-03

(b) Calculate the magnetic field of the 310 turn solenoid after 0.900 s.
Correct: Your answer is correct. T 8.85e-03

(c) Calculate the area of the 4-turn coil.
Correct: Your answer is correct. m2 6.16e-04

(d) Calculate the change in the magnetic flux through the 4-turn coil during the same period.
Correct: Your answer is correct. Wb 29e-07

(e) Calculate the average induced emf in the 4-turn coil.
Incorrect: Your answer is incorrect.

Explanation / Answer

(e) emf = -4pi x (0.014^2)(4pi x 10^-7)(310/0.22)(5-2.3/)0.9 = 130.84 e-07 V

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