Suppose the series resistors in Example 18. 3 are now 4. 00 and 8. 00 while the

Question

Suppose the series resistors in Example 18. 3 are now 4. 00 and 8. 00 while the parallel resistors are 3. 00 (top) and 6. 00 (bottom), and the battery provides an emf of 45. 0 V. Find (a) the equivalent resistance and (b) the currents I, I1, I2. Req = I = A I1 = A I2 = A Find the equivalent resistance of the circuit. The 8. 0 and 4. 0 resistors are in series, so use the sum rule to find the equivalent resistance between a and b. The 6. 0 and 3. 0 resistors are in parallel, so use the reciprocal-sum rule to find the equivalent resistance between b and c (don't forget to invert!) In the new diagram, 18. 11b, there are now two resistors in series. Combine them with the sum rule to find the equivalent resistance of the circuit. Find the current in each resistor if a 42 V battery is connected between points a and c. Find the current in the equivalent resistor in Figure 8. 11c, which is the total current. Resistors in series all carry the same current, so this is the current in the 12 in Figure 8. 11b, and also in the 8. 0 and 4. 0 resistors in Figure 8. 11a. Apply the junction rule to point b. The 6. 0 and 3. 0 resistors are in parallel, so the voltage drops across them are the same. Substitute this result into Equation (1), with I = 3. 0 A. Req = R1 + R2 = 8. 0 + 4. 0 = 12 Req = 2. 0 Req = R1 + R2 = R2 + 2. 0 = I = I1 + I2

Explanation / Answer

14ohm I=3Ampere I1=1Amp I2=2Amp

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