Find the magnetic moment of the circular loop and the magnetic torque exerted on

Question

Find the magnetic moment of the circular loop and the magnetic torque exerted on it. First, calculate the enclosed area of the circular loop. Calculate the magnetic moment of the loop. Now substitute values for the magnetic moment, magnetic field, and theta into Equation 19. 9b. Find the magnetic moment of the rectangular coil and the magnetic torque exerted on it. Calculate the area of the coil. Calculate the magnetic moment of the coil. Substitute values into Equation 19. 9b. A = pir2 = pi(1. 08 m)2 = 3. 66 m2 mu = IAN = (1. 70 A)(3. 66 m2)(1) mu = A. m2 tau = muB sin theta = mu(0. 475 T)(sin 30. 0 degree ) tau = N. m A = L times H = (2. 00 m)(3. 00 m) = 6. 00 m2 mu = IAN = (1. 70 A)(6. 00 m2)(3) mu = A. m2 tau = muB sin theta = mu(0. 475 T)(sin 30. 0 degree ) tau = N. m In calculating a magnetic torque, it's not strictly necessary to calculate the magnetic moment. Instead, Equation 19. 9a can be used directly. Suppose a right triangular coil with base of 2. 05 m and height 2. 80 m having two loops carries a current of 1. 70 A as shown in Figure 19. 16c. Find the magnetic moment and the torque on the coil. The magnetic field is again 0. 475 T and the angle is 30. 0 degree. moment A. m2 torque N. m

Explanation / Answer

a) = 6.222 Am2, = 1.477725 Nm

b) = 30.6 Am2, = 7.2675 Nm

19.3) = IAN = 0.5*2.05*2.8*1.7*2 = 9.758 Am2

= Bsin = 9.758*0.475*sin30 = 2.317525 Nm

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