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hat are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)? E

ID: 2160189 • Letter: H

Question


hat are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

Ex=N/C

Ey = 0 N/C


(b) Now the positive and negative charge switch places. The magnitude of the charges is still 9.8 C where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.


What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

Ex=N/C

Ey = 0 N/C

(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 9.8 ½C but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative. hat are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)? Ex=N/C Ey = 0 N/C (b) Now the positive and negative charge switch places. The magnitude of the charges is still 9.8 ½C where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative. What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)? Ex=N/C Ey = 0 N/C

Explanation / Answer

since due to symmetry y component of electric field is cancelled and net in y component direction will be zero and eacof their electric field in x component are equal and same direction so they will add up so Ex = 2{(9*10^9)*(9.8*10^-6)/25} = 7.056 *(10^3) N/c