Two coaxial cylindrical conductors are shown in cross-section above. The inner c

Question

Two coaxial cylindrical conductors are shown in cross-section above. The inner cylinder has radiusa= 2 cm, length 10 m and caries a total charge ofQinner= + 8 nC (1 nC = 10-9C). The outer cylinder has an inner radiusb= 6 cm, outer radiusc= 7 cm, length 10 m and carries a total charge ofQouter= - 16 nC (1 nC = 10-9C). What isEx, the x-component of the electric field at point P which is located at the midpoint of the length of the cylinders at a distancer= 4 cm from the origin and makes an angle of 30owith the x-axis?

Explanation / Answer

E=F/q which eventually will get to kQ(source)/r^2 so by using this equation you simply plug in what is given. if i am not mistaken about the picture, P is right above q2 so that won't affect the x-component. So, you will have Ex(P)=(9E9)*(-3.9E-6)/(.067^2+.067^2). this will give you the magnitude of the electric field produced by q1. all thats left is to multiply your answer by a sin(45) and voila, there's your answer! This should be your final answer (-2764474.05 N/C) for the second part you do the same, use the formula but this time q2 will affect it because you are looking for the y-component.

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