A bag of cement weighing 350 N hangs in equilibrium from three wires as suggeste
ID: 2165658 • Letter: A
Question
A bag of cement weighing 350 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make angles ?1 = 59.0? and ?2 = 39.0? with the horizontal. Assuming the system is in equilibrium, find the tensions T1, T2, and T3 in the wires.
T1=N
T2=N
T3=N
A bag of cement weighing 350 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make angles ?1 = 59.0? and ?2 = 39.0? with the horizontal. Assuming the system is in equilibrium, find the tensions T1, T2, and T3 in the wires.Explanation / Answer
For a system in equilibrium Summation of forces along the horizontal direction equals zero (Considering the Forces at the intersection of the wires) ?F? = 0 0 = T2 (cos 59°) - T1(cos39°) T1(.515) = T2(.777) T1 = (1.509)T2 Summation of forces Vertical equals zero ?Fv= 0 0 = T1 (sin59) + T2(si39°) - T3 0 = T1(.85) + T2(.62) - T3 ...................T3 = W = 350N ....................T1 = (1.509)T2 0 = (1.509)T2(.85) + T2(.62) - 350 ...= (1.28)T2 + (.62)T2 - 350 350 = (1.902) T2 T2 = 183.9N T1 = (1.509)(183.9 = 277.5N T3= 350n
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