A bag of cement weighing 400 N hangs in equilibrium from three wires as suggeste

Question

A bag of cement weighing 400 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make angles ?1 = 61.0

A bag of cement weighing 400 N hangs in equilibrium from three wires as suggested in the figure below. Two of the wires make angles ?1 = 61.0 degree and ?2 = 42.0 degree with the horizontal. Assuming the system is in equilibrium, find the tensions T1, T2, and T3 in the wires.

Explanation / Answer

T1*cos61 = T2*cos42 => 0.485*T1 = 0.74*T2 => T1 = 1.53 *T2 T3 = 400 N T1*sin 61 + T2*sin42 = T3 => 1.53*T2*0.875 + 0.67*T2 = 400 => T2 = 200 N T1 = 306 N

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