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Problem 22.28
For the circuit in the Figure (Figure 1) , R = 300 ohm , L = 0.500H and C = 0.600 microF The voltage amplitude of the source is 120V .

Part A
What is the resonance frequency of the circuit? in Hz

Part B
Sketch the phasor diagram at the resonance frequency.
Draw the current I_R, I_C and I_L phasors with their tails at the origin of the coordinate system. The orientation and the exact length of your phasors will be graded.

Part C
At the resonance frequency, what is the current amplitude through the source? in A

Part D
At the resonance frequency, what is the current amplitude through the resistor? Through the inductor? Through the branch containing the capacitor?
Enter your answer as three numbers separated with commas.
I_R,I_L,I_C

Explanation / Answer

a)=1/LC = 1.825 * 103

f=/2=290.57 Hz

b) resistance and total current are along voltage- direction.IL,IC are opposite to each other.

c)at resonance, impedance=0

I=V/R=120/300=0.4 A

d)IR=I=0.4

IL=V/L=0.13 A

IC=VC=0.13 A

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