A ball is thrown horizontally off a cliff with an initial speed of 16.0 m/s and

Question

A ball is thrown horizontally off a cliff with an initial speed of 16.0 m/s and falls to the valley floor. (Ignore air resistance). Find the total time the ball is in the air after its release until it hits the ground. Find the magnitude and directions of its velocity v immediately before it hits the ground. Express the direction as a negative angle with respect to the x axis. There is a diagram given that shows the y value as being 56.0 m.

Explanation / Answer

S = 0.5*9.81*t^2 =>t = sqrt(56/(0.5*9.8)) = 3.38062sec v^2 = 2aS =>v = 33.147m/sec So velocity = sqrt((33.14694556^2)+(16^2)) = 36.8065m/sec Direction = -64.233degrees

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