At one instant a bicyclist is 55 m due east of a park\'s flagpole, going due sou

Question

At one instant a bicyclist is 55 m due east of a park's flagpole, going due south with a speed of 12 m/s. Then, 21 s later, the cyclist is 85 m due north of the flagpole, going due east with a speed of 12 m/s. For the cyclist in this 21 s interval, find each of the following.

(a) displacement

?r = ____m, ____ north of due west

(b) average velocity

Vav = ____ m/s, _____ north of due west

(c) average acceleration

Aav = ____ m/s^2, _____ north of due east

PLEASE PROVIDE STEPS FOR 5 STAR RATING. :) I'D LIKE TO LEARN HOW TO SOLVE THANKS!!

Explanation / Answer

ht so for part (a) i used 50hat{i} and 70hat{j} in the equation above to get 86.023m then inversetan (70/50) to get 54.462 degrees. i thought that 54.462 was the angle for norht of due east, but its the correct answer. It would be nice if someone could explain that to me. then with part (b) im completely lost, i tried plugging in the 7m/s and the 20m/s the same way as i did for the displacement but got 21.190 degrees. thats wrong and now iv been stuck forever it seems. any help would be much appreciated. thanks!

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