When you apply a horizontal force of 42 N to a block, the block moves across the

Question

When you apply a horizontal force of 42 N to a block, the block moves across the floor at a constant speed (?k = ?s).

(a) What happens if instead you apply a force of 34 N to the block initially at rest? (b) When you apply a force of 34 N to the block initially at rest, what is the magnitude of the horizontal component of the force that the floor exerts on the block?
Fhor = N (c) What happens if instead you exert a force of 49 N? The block moves at a constant speed, but it moves faster. The block doesn't move. The block accelerates (the speed continually increases). (d) When you apply a force of 49 N, what is the magnitude of the horizontal component of the force that the floor exerts on the block?
Fhor = N When you apply a horizontal force of 42 N to a block, the block moves across the floor at a constant speed (?k = ?s). (a) What happens if instead you apply a force of 34 N to the block initially at rest? The block doesn't move. The block decelerates (the speed continually decreases). The block moves at a constant speed, but it moves more slowly. Incorrect: Your answer is incorrect. (b) When you apply a force of 34 N to the block initially at rest, what is the magnitude of the horizontal component of the force that the floor exerts on the block? Fhor = N (c) What happens if instead you exert a force of 49 N? The block moves at a constant speed, but it moves faster. The block doesn't move. The block accelerates (the speed continually increases). (d) When you apply a force of 49 N, what is the magnitude of the horizontal component of the force that the floor exerts on the block?

Explanation / Answer

c

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