When you apply a horizontal force of 48 N to a block, the block moves across the

Question

When you apply a horizontal force of 48 N to a block, the block moves across the floor at a constant speed (mu k = mu s). What happens if instead you apply a force of 41 N to the block initially at rest? The block decelerates (the speed continually decreases). The block doesn't move. The block moves at a constant speed, but it moves more slowly. When you apply a force of 41 N to the block initially at rest, what is the magnitude of the horizontal component of the force that the floor exerts on the block? Fhor = N What happens if instead you exert a force of 53 N? The block moves at a constant speed, but it moves faster. The block doesn't move. The block accelerates (the speed continually increases). When you apply a force of 53 N, what is the magnitude of the horizontal component of the force that the floor exerts on the block?Fhor = N

Explanation / Answer

Static friction is the force between two objects that are not moving relative to each other. kinetic friction is the force between two objects that are moving relative to each other. here both are equal a) if only 41 is applied it doesnt move since minimum 48n is required to move the block 2)when the applied force is 41 N which is less than fL, the body can't move and the applied force becomes equal to the static friction fs hence the magnitude of horizontal component of the force of floor = fs = F = 41 Nc)since 53 is more than required block accelerates 4) in this case, since the applied force is 53 N which is larger than fL, the body will be accelrating. however, the kinetic friction still will be fk = 48 N which is the horizontal component of the force of the floor.

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