1. On paper, replicate the following segment of DNA: 5, A T C G G C T A C G T T
ID: 217085 • Letter: 1
Question
1. On paper, replicate the following segment of DNA: 5, A T C G G C T A C G T T C A C 3, 3'TAGCCGATGCAAGTG 5 a. Show the direction of replication of the new strands and explain what causes lagging and leading strands to show different patterns of replication. b. Describe the actions of all of the enzymes involved in replication of a DNA molecule. 2. The following sequence represents triplets on DNA: TAC CAG ATA CAC TCC CCT GCG ACT mRNA codons tRNA anticodon Give the mRNA codons and tRNA anticodons that correspond with this sequence Using this piece of DNA, show a deletion, an insertion, a substitution, and nonsense mutations. Which ones are frameshift mutations? (Use the universal code to determine this.) a. b. 3. Explain which type of operon is functioning here. How would another operon differ from this? 0 Enryne aye production 7 DNA RNAExplanation / Answer
2) (a)DNA---3' TAC CAG ATA CAC TCC CCT GCG ACT
mRNA---5' AUG GUC UAU GUG AGG GGA CGC UGA 3'
tRNA anticodon--methionine valine tyrosine valine arginine glycine arginine
b) DNA---3' TAC CAG ATA CAC TCC CCT GCG ACT 5'
After deletion 3' TAC CAA TAC ACT CCC CTG CGA CT 5'
After insertion 3' TAC CAG TAT ACA CTC CCC TGC GAC T 5'
A substitution 3' TAC CAT ATA CAC TCC CCT GCG ACT 5'
non sense mutation 3' TAC UAG ATA CAC TCC CCT GCG ACT 5'
Insertion and deletion are frameshift mutation since with the insertion or deletion of a nucleotide there was shift in the reading frame of the DNA. A nonsense mutation was the one where a change in a nucleotide changes the codon to a stop codon and leads to premature termination of translation.
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