Two charges lie along the x-axis as in figure. A positive charge q1 = 20 mC is l

Question

Two charges lie along the x-axis as in figure. A positive charge q1 = 20 mC is located at x = -2 m, and another positive charge q2 = 5 mC is at x = 4 m. Answer the following questions. Find the location, P where the resultant electric field is zero. Find the location, x. Find the magnitude force exerted by the charge q2 and direction at the x = -2m. Consider the two point charges, where q1 = 72 nC and q2 = -18 nC. Find the magnitude of the electric field at point P. Find the direction of the electric field at point P. Assume with the angle from the positive x-axis.

Explanation / Answer

20/(x+2)^2=5/(4-4)^2 x=2cm F=qE=29.94kN directio is -ve x E=72*8.98*10^4/12^2(-j)+8.98*18*10^4/9^2i |E|=4.91*10^4N/C theta=66 from x axis clockwise

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