A person stands on a scale in an elevator. As the elevator starts, the scale has

Question

A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 600 N. As the elevator later stops, the scale reading is 388 N. Assume the magnitude of the acceleration is the same during starting and stopping.
(a) Determine the weight of the person.
N

(b) Determine the person's mass.
kg

(c) Determine the magnitude of acceleration of the elevator.
m/s2

Explanation / Answer

When the Elevator go Upward ==> Reading = m(g+a) = 594 ==>When Elevator Stops ==>Reading = Weight = mg = 388 N (Answer) ==>m = 388/9.8 ==> m = 39.59 Kg (Answer) ==> Therefore ==>39.59*(9.8+a) = 594 ==> a = 5.2 m/sec^2 (Answer)

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