1) Why are two conducting paths needed from any voltage source? Why Can\'t an el
ID: 2175479 • Letter: 1
Question
1) Why are two conducting paths needed from any voltage source? Why Can't an electrical device operate by just being connected to a single hot wire?2) Explain why the direction of electron flow in a circuit is from negative to positive .
3) In what ways are simple electric circuits analogous to fluid-circulation systems? In what ways do they differ?
4)What are effective voltage, current , and power?
5) a) What is the resistance of ten 100-W light bulbs connected in parallel.b) in series? the resistance of a 100-W 120-V light bulb is 144 ohm ignoring the temperature dependence of resistance.
6) a)Calculate the currents used by and resistances of 25- and 60-W light bulbs designed to operate on 120-V electricity. b) If these two bulbs are connected in series to a 120-V source, what power is consumed by each assuming that their resistances are the same as found in a)?
7) Will a 120-V hospital circuit protected by a 15-A circuit breaker be able to operate a 200-W ECG monitor, a 1200-W microwave oven , and eight 40-W lights simultaneously?
Explanation / Answer
1) two conducting paths are needed to complete the circuit. electric current which is constituted by flow of electrons need to flow from for which two conducting paths are needed. So a single wire cannot work. 2)electrons being negatively charged flow to positive terminal from negative terminal. 3)they are similar in terms of ohm's law. Higher the driving potential, higher is the flow/current. 4)effective current/power/voltage is the real component of complex power which has both real and imaginary components. 5) in parallel net resistance = (R/10) in series net resistance = 10R put R=144 to get your answer. 6) power = i^2*R = V^2/R given V =120V, for P = 25W, R = 576 ohm, so i = 0.2083A for P = 60W, R = 240 ohm, so i = 0.5A in series, net resistance becomes = 576+240 = 816 ohms current drawn = 120/816 = 0.147A total power dissipated = i^2*(240+576) = 17.65W 7) find resistance of each device by formula R = V^2/P you have P for each device and V=120V then find the equivalent resistance of all these devices assuming they are in parallel. then divide the voltage (120V) by value of resistance so obtained to get current. if this current > 15A, these devices will not operate pls solve yourself accordingly following these steps
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