The Earth orbits the Sun once per year. What is the centripetal force keeping th

Question

The Earth orbits the Sun once per year.

What is the centripetal force keeping the Earth in orbit?

I found how far the earth travels in one year (340,000,000), The Earths Tangential velocity (29814 m/s), and the centripetal acceleration of the earth (5.928e-3 m/s^2), but what is the centripetal force keeping the earth in orbit?

I already know the formula (Fc = m. v^2/r), but I can't for the life of me get the correct answer in Newtons.

T = 1 year (convert to seconds)
r = 1.5e+11 meters
m = 6e+24 kg

Explanation / Answer

Fc = m. v^2/r
M is the star’s mass, m is the planet’s mass, and R is the distance between the planet and star. It’s negative because it’s trying to decrease R.
v is the “tangential velocity” (how fast the planet is moving around the star, and not counting motion toward or away from the star).
m = (6 e+24) = 6×10^24
r = 1.5 e+11 = 1.5 x 10^11
Fc = (6 x 10^24) * (29814 ^2) / (1.5 x 10^11)
Fc = 3.555498384 x 1022 N

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