A charged capacitor is discharged through a resistor. The current I(t) through t

Question

A charged capacitor is discharged through a resistor. The current I(t) through this resistor, determined by measuring the voltage VR(t) = I(t)R with an oscilloscope, is shown in the graph. The total energy dissipated in the resistor is 1.90 10-4 J.

(a) Find the capacitance C, the resistance R, and the initial charge Q0 on the capacitor. [Hint: You will need to solve three equations simultaneously for the three unknowns. You can find both the initial current and the time constant from the graph.] C = F R = ? Q0 = C

(b) At what time is the stored energy in the capacitor 5.20 10-5 J? s

Explanation / Answer

E=(0.5)*c*v^2 V=I*R Q=Q0*exp(-t/cR) solve these three equations to get required values

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