A string under a tension of 40.0 N is used to whirl a rock in a horizontal circl

Question

A string under a tension of 40.0 N is used to whirl a rock in a horizontal circle of radius 2.75 m at a speed of 20.3 m/s on a frictionless surface as shown in the figure below. As the string is pulled in, the speed of the rock increases. When the string is 1.00 m long and the speed of the rock is 50.5 m/s, the string breaks. What is the breaking strength, in newtons, of the string?

A string under a tension of 40.0 N is used to whirl a rock in a horizontal circle of radius 2.75 m at a speed of 20.3 m/s on a frictionless surface as shown in the figure below. As the string is pulled in, the speed of the rock increases. When the string is 1.00 m long and the speed of the rock is 50.5 m/s, the string breaks. What is the breaking strength, in newtons, of the string?

Explanation / Answer

Initially F = mv^2/r =>40 = m x 20.3^2 /2.75 =>mass of the rock = .266 At final stage:- =>F = mv^2/r =>F = 0.266 x 50.5^2/1 = 680.7 N

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