A string is wrapped several times around the rim of a small hoop with radius 8cm

Question

A string is wrapped several times around the rim of a small hoop with radius 8cm and mass 0.18kg The free end of the string is held in place and the hoop is released from rest. After the hoop has descended 60.0cm , calculate

the angular speed of the rotating hoop and

the speed of its center.

A string is wrapped several times around the rim of a small hoop with radius 8cm and mass 0.18kg The free end of the string is held in place and the hoop is released from rest. After the hoop has descended 60.0 cm , calculate the angular speed of the rotating hoop and the speed of its center.

Explanation / Answer

substitute the values in these equations and u can get the answers

PE = mgh = KE = (mv^2 + I?^2)/2 = (mv^2 + mr^2?^2)/2 = m(v^2 + (r?)^2)/2 = mv^2
2. v = sqrt(gh)
1. ? = v/r

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