In a pole sliding game among friends, a 93kg man makes a total vertical drop of

Question

In a pole sliding game among friends, a 93kg man makes a total vertical drop of 7.4m while gripping the pole which exerts and upward force (call it Fp) on him. Starting from rest and sliding with a constant acceleration, his slide takes 2.3s. a) draw the man's free body diagram being sure to label all the forces. b) what is the magnitude of the upward force exerted on the man by the pole? c) a friend whose mass is only 74kg, slides down the same distance, but the pole force is only 76% of the force on his buddy.How long did the second person's slide take?

Explanation / Answer

Initial speed ( u ) = 0 Distance ( s ) = 8 Time ( t ) = 2.4 Acceleration = what we need to find s = ut + 1/2 at^2 8 = 1/2 ( a ) ( 2.4 )^2 8 = 1/2 ( 5.76a ) 5.76a = 16 a = 2.8 m/s^2 Then use Force = Mass * Acceleration = 86 * 2.8 = 241N

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