Two speakers A and B are 3.50 apart, and each one is emitting a frequency of 444
ID: 2183886 • Letter: T
Question
Two speakers A and B are 3.50 apart, and each one is emitting a frequency of 444Hz . However, because of signal delays in the cables, speaker A is one-fourth of a period ahead of speaker B .For points far from the speakers, find all the angles relative to the centerline (see the figure (Figure 1) ) at which the sound from these speakers cancels. Include angles on both sides of the centerline. The speed of sound is 340m/s.
A. Type the angles for points above the centerline in increasing order separating them with commas.
B. Type the angles for points below the centerline in increasing order separating them with commas.
Explanation / Answer
sin(x)=(m(L)+L/4)/d a) 3.14,15.9,29.5,45.4,68.6 b) 9.45,22.5,37.0,55.2
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