A blue car with mass mc = 459.0 kg is moving east with a speed of vc = 19.0 m/s

Question

A blue car with mass mc = 459.0 kg is moving east with a speed of vc = 19.0 m/s and collides with a purple truck with mass mt = 1245.0 kg that is moving south with a speed of vt = 10.0 m/s . The two collide and lock together after the collision. 1) What is the magnitude of the initial momentum of the car? 2) What is the magnitude of the initial momentum of the truck? 3) What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East) 4) What is the magnitude of the momentum of the car-truck combination immediately after the collision? 5) What is the speed of the car-truck combination immediately after the collision? 6) Compare the initial and final kinetic energy of the total system before and after the collision:

Explanation / Answer

1) What is the magnitude of the initial momentum of the car?

pc = mc vc = 459.0 * 19.0 = 8721 Kg.m/s

2) What is the magnitude of the initial momentum of the truck?

pt = mt vt = 1245.0 * 10.0 = 12450 Kg.m/s

3) What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East)

=Arctan(12450/8721) = 54.989 55.0 degrees

4) What is the magnitude of the momentum of the car-truck combination immediately after the collision?

(8721*8721+12450*12450) = 15201 Kg.m/s

5) What is the speed of the car-truck combination immediately after the collision?

15201/(459+1245) = 8.9208 8.92 m/s

6) Compare the initial and final kinetic energy of the total system before and after the collision:

before:

0.5*459*19*19 + 0.5*1245*10*10 = 145100 J

after:

0.5 * (459+1245) * 8.9208 * 8.9208 = 67803 J

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