A 7 g bullet is travelling at a speed of 200 m/s towards a 650 g block which lie

Question

A 7 g bullet is travelling at a speed of 200 m/s towards a 650 g block which lies on a horizontal and frictionless surface at the end of a string of length 1 m. The bullet's trajectory is tangent to the circle defined by the string. The bullet goes completely through the block and exits with a speed of one-half its initial speed.
A)What is the velocity of the 650 g block after the bullet exits?
B)After the collision, the 650 g block moves in a circle defined by the string. What is the tension in the string?

Thanks!

Explanation / Answer

a) 0.007*200 + 0 = 0.650v + 0.007*100 V = 1.07692 m/s b) Tension = mv^2/r = 0.7538 N

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