A 68 year old Caucasian man is admitted to the hospital for treatment of hemolyt

Question

A 68 year old Caucasian man is admitted to the hospital for treatment of hemolytic anemia. Records from two years ago indicate the patient is O positive and received two units of blood at the time.The technologist types the patient’s blood as Rh negative. How could this be possible?

A. The technologist forgot to add anti-D to the test tube

B. The patient is a D partial

C. The patient is a weak D

D. All of the above

The patient has developed an anti-E, what kind of blood should he receive?

A. R1r or rr

B. R1R2 or r”r”

C. R2r or r”r

D. R2R2 or ry

The patient types serologically D+ C+ E+ c+ e+ what is his most likely genotype?

A. DCE/dce

B. DcE/DCe

C. DcE/dce

E. Dce/dcE

Explanation / Answer

There is a possibility that the technologist forget to add the anit D in the test tube, that have gven the false positive that the patient is Rh –ve. As the patient was under supervision from last two years, his Rh report should be there.

Then there could be possibility of person having weak or partial RhD. As, weak D and partial D expressions are caused by a large number of RHD alleles and variations of the antigen structure of RhD. Weak and partial D result in quantitative and qualitative changes in Rh protein expression respectively.

Ans. D.R2R2 or ry

will be the blood type of the patient with anti E. This is deduced with the multiple alleles weiner. In which only R2 and rY represent anti E

Ans. A. DCE/dce

is the correct answer. It is because in this crossing there will be atleast one D+C+E+d+c+e+.

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