A 66.0 kg man floats in fresh water with 3.00% of his volume above water when hi

Question

A 66.0 kg man floats in fresh water with 3.00% of his volume above water when his lungs are empty, and 5.00% above water when his lungs are full. Calculate the volume of air he inhales--called his lung capacity--in liters. A 66.0 kg man floats in fresh water with 3.00% of his volume above water when his lungs are empty, and 5.00% above water when his lungs are full. Calculate the volume of air he inhales--called his lung capacity--in liters. A 66.0 kg man floats in fresh water with 3.00% of his volume above water when his lungs are empty, and 5.00% above water when his lungs are full. Calculate the volume of air he inhales--called his lung capacity--in liters.

Explanation / Answer

Vair =V V'   -----------(1)

where V is the volume of a man when lungs are full and V' is the volume of man when lungs are empty.

fraction submerged = object /water  = (m/V)/w

Gives ,  V =(m/0.950)/w   and  V’ = (m/0.970) /w

From (1)  

Vair =VV' = m/w *(1/0.950 - 1/0.970) = (66/1000)*(1/0.950 - 1/0.970) = 0.001432 m^3  = 1.4*10^-3 m^3

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.